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(A) quadratic polynomial is given by the formula: $p(x) = k[x^2 - (	ext{sum of zeros})x + (	ext{product of zeros})]$.Given:Sum of zeros $= \frac{1}{

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$k(4x^2 - x - 4)$

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(A) quadratic polynomial is given by the formula: $p(x) = k[x^2 - (	ext{sum of zeros})x + (	ext{product of zeros})]$.Given:Sum of zeros $= \frac{1}{4}$Product of zeros $= -1$Substituting these values into the formula:$p(x) = k[x^2 - (\frac{1}{4})x + (-1)]$$p(x) = k[x^2 - \frac{1}{4}x - 1]$To simplify,we can take $k = 4$:$p(x) = 4[x^2 - \frac{1}{4}x - 1] = 4x^2 - x - 4$.Thus,the polynomial is $k(4x^2 - x - 4)$.

Obtain a quadratic polynomial with the following conditions:
The sum of the zeros $= \frac{1}{4}$;
The product of the zeros $= -1$.

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Obtain a quadratic polynomial with the following conditions:The sum of the zeros $= \frac{1}{4}$;The product of the zeros $= -1$.